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2141214113 = 3169071423
BaseRepresentation
bin111111110100000…
…0101010110100001
312112020001221120102
41333220011112201
513341122322423
6552245352145
7104030006513
oct17750052641
95466057512
102141214113
119a9728945
124b9108655
132817bb1cc
14164537bb3
15c7ea8c28
hex7fa055a1

2141214113 has 4 divisors (see below), whose sum is σ = 2210285568. Its totient is φ = 2072142660.

The previous prime is 2141214091. The next prime is 2141214149. The reversal of 2141214113 is 3114121412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2141214113 - 222 = 2137019809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2141214193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34535681 + ... + 34535742.

It is an arithmetic number, because the mean of its divisors is an integer number (552571392).

Almost surely, 22141214113 is an apocalyptic number.

It is an amenable number.

2141214113 is a deficient number, since it is larger than the sum of its proper divisors (69071455).

2141214113 is an equidigital number, since it uses as much as digits as its factorization.

2141214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69071454.

The product of its digits is 192, while the sum is 20.

The square root of 2141214113 is about 46273.2548347315. The cubic root of 2141214113 is about 1288.9024001031.

Adding to 2141214113 its reverse (3114121412), we get a palindrome (5255335525).

The spelling of 2141214113 in words is "two billion, one hundred forty-one million, two hundred fourteen thousand, one hundred thirteen".

Divisors: 1 31 69071423 2141214113