Base | Representation |
---|---|
bin | 1100011101101010100… |
… | …0011100100011011011 |
3 | 202110200111020211020211 |
4 | 3013122220130203123 |
5 | 12002010041331212 |
6 | 242211021231551 |
7 | 21320062103335 |
oct | 3073250344333 |
9 | 673614224224 |
10 | 214121433307 |
11 | 82898a70041 |
12 | 355b8a025b7 |
13 | 17264b37482 |
14 | a513768455 |
15 | 58830929a7 |
hex | 31daa1c8db |
214121433307 has 2 divisors, whose sum is σ = 214121433308. Its totient is φ = 214121433306.
The previous prime is 214121433247. The next prime is 214121433311. The reversal of 214121433307 is 703334121412.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214121433307 is a prime.
It is not a weakly prime, because it can be changed into another prime (214121433007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107060716653 + 107060716654.
It is an arithmetic number, because the mean of its divisors is an integer number (107060716654).
Almost surely, 2214121433307 is an apocalyptic number.
214121433307 is a deficient number, since it is larger than the sum of its proper divisors (1).
214121433307 is an equidigital number, since it uses as much as digits as its factorization.
214121433307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 214121433307 its reverse (703334121412), we get a palindrome (917455554719).
The spelling of 214121433307 in words is "two hundred fourteen billion, one hundred twenty-one million, four hundred thirty-three thousand, three hundred seven".
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