Base | Representation |
---|---|
bin | 11111001010001010110… |
… | …010111011110100000011 |
3 | 21120200212110120002110122 |
4 | 133022022302323310003 |
5 | 240040210403241121 |
6 | 4315355225250455 |
7 | 310461325300445 |
oct | 37121262736403 |
9 | 7520773502418 |
10 | 2141222321411 |
11 | 7560a61a7108 |
12 | 2a6b97033a2b |
13 | 126bbb434774 |
14 | 758c857c495 |
15 | 3aa711985ab |
hex | 1f28acbbd03 |
2141222321411 has 4 divisors (see below), whose sum is σ = 2141232084024. Its totient is φ = 2141212558800.
The previous prime is 2141222321393. The next prime is 2141222321419. The reversal of 2141222321411 is 1141232221412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2141222321411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2141222321419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4544570 + ... + 4993551.
It is an arithmetic number, because the mean of its divisors is an integer number (535308021006).
Almost surely, 22141222321411 is an apocalyptic number.
2141222321411 is a deficient number, since it is larger than the sum of its proper divisors (9762613).
2141222321411 is an equidigital number, since it uses as much as digits as its factorization.
2141222321411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9762612.
The product of its digits is 1536, while the sum is 26.
Adding to 2141222321411 its reverse (1141232221412), we get a palindrome (3282454542823).
Subtracting from 2141222321411 its reverse (1141232221412), we obtain a palindrome (999990099999).
The spelling of 2141222321411 in words is "two trillion, one hundred forty-one billion, two hundred twenty-two million, three hundred twenty-one thousand, four hundred eleven".
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