Base | Representation |
---|---|
bin | 11111001010001111011… |
… | …111100100101011110001 |
3 | 21120201001221212002021222 |
4 | 133022033133210223301 |
5 | 240040341042211032 |
6 | 4315411122354425 |
7 | 310463303211125 |
oct | 37121737445361 |
9 | 7521057762258 |
10 | 2141301132017 |
11 | 756136735743 |
12 | 2a6bb94bba15 |
13 | 126c01869668 |
14 | 758d4c15585 |
15 | 3aa78064a12 |
hex | 1f28f7e4af1 |
2141301132017 has 2 divisors, whose sum is σ = 2141301132018. Its totient is φ = 2141301132016.
The previous prime is 2141301131969. The next prime is 2141301132071. The reversal of 2141301132017 is 7102311031412.
Together with next prime (2141301132071) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1645740042496 + 495561089521 = 1282864^2 + 703961^2 .
It is a cyclic number.
It is not a de Polignac number, because 2141301132017 - 220 = 2141300083441 is a prime.
It is not a weakly prime, because it can be changed into another prime (2141301132317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070650566008 + 1070650566009.
It is an arithmetic number, because the mean of its divisors is an integer number (1070650566009).
Almost surely, 22141301132017 is an apocalyptic number.
It is an amenable number.
2141301132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141301132017 is an equidigital number, since it uses as much as digits as its factorization.
2141301132017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 2141301132017 its reverse (7102311031412), we get a palindrome (9243612163429).
The spelling of 2141301132017 in words is "two trillion, one hundred forty-one billion, three hundred one million, one hundred thirty-two thousand, seventeen".
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