Base | Representation |
---|---|
bin | 11111001010011010010… |
… | …111110110000011101011 |
3 | 21120201112200022020022101 |
4 | 133022122113312003223 |
5 | 240041224303433103 |
6 | 4315441202434231 |
7 | 310500650506231 |
oct | 37123227660353 |
9 | 7521480266271 |
10 | 2141483655403 |
11 | 75621a771214 |
12 | 2a704a662977 |
13 | 126c30614c71 |
14 | 75911168951 |
15 | 3aa890baa1d |
hex | 1f29a5f60eb |
2141483655403 has 2 divisors, whose sum is σ = 2141483655404. Its totient is φ = 2141483655402.
The previous prime is 2141483655373. The next prime is 2141483655499. The reversal of 2141483655403 is 3045563841412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2141483655403 - 25 = 2141483655371 is a prime.
It is not a weakly prime, because it can be changed into another prime (2141483655803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070741827701 + 1070741827702.
It is an arithmetic number, because the mean of its divisors is an integer number (1070741827702).
Almost surely, 22141483655403 is an apocalyptic number.
2141483655403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141483655403 is an equidigital number, since it uses as much as digits as its factorization.
2141483655403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1382400, while the sum is 46.
The spelling of 2141483655403 in words is "two trillion, one hundred forty-one billion, four hundred eighty-three million, six hundred fifty-five thousand, four hundred three".
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