Search a number
-
+
214201210403 = 573493735047
BaseRepresentation
bin1100011101111101100…
…0110001011000100011
3202110220001100220212002
43013133120301120203
512002141002213103
6242222551154215
721322051150535
oct3073730613043
9673801326762
10214201210403
1182929aa9824
123561b67596b
131727851a25b
14a5201b3855
15588a0a0488
hex31df631623

214201210403 has 4 divisors (see below), whose sum is σ = 214205002800. Its totient is φ = 214197418008.

The previous prime is 214201210387. The next prime is 214201210439. The reversal of 214201210403 is 304012102412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 214201210403 - 24 = 214201210387 is a prime.

It is a super-2 number, since 2×2142012104032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214201210463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1810175 + ... + 1924872.

It is an arithmetic number, because the mean of its divisors is an integer number (53551250700).

Almost surely, 2214201210403 is an apocalyptic number.

214201210403 is a deficient number, since it is larger than the sum of its proper divisors (3792397).

214201210403 is an equidigital number, since it uses as much as digits as its factorization.

214201210403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3792396.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 214201210403 its reverse (304012102412), we get a palindrome (518213312815).

The spelling of 214201210403 in words is "two hundred fourteen billion, two hundred one million, two hundred ten thousand, four hundred three".

Divisors: 1 57349 3735047 214201210403