Base | Representation |
---|---|
bin | 1001101111110010010101… |
… | …10111111111110010110001 |
3 | 2210212222200120212011022001 |
4 | 10313321022313333302301 |
5 | 10302130034102001431 |
6 | 113330125554214001 |
7 | 4341331156360540 |
oct | 467711267776261 |
9 | 83788616764261 |
10 | 21433143000241 |
11 | 691382150aa15 |
12 | 24a1a78284301 |
13 | bc61a148504b |
14 | 5415264a0157 |
15 | 2727d2a0de61 |
hex | 137e4adffcb1 |
21433143000241 has 16 divisors (see below), whose sum is σ = 24524243251200. Its totient is φ = 18349349886288.
The previous prime is 21433143000239. The next prime is 21433143000253. The reversal of 21433143000241 is 14200034133412.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 21433143000241 - 21 = 21433143000239 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21433143000281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 296087590 + ... + 296159968.
It is an arithmetic number, because the mean of its divisors is an integer number (1532765203200).
Almost surely, 221433143000241 is an apocalyptic number.
It is an amenable number.
21433143000241 is a deficient number, since it is larger than the sum of its proper divisors (3091100250959).
21433143000241 is an equidigital number, since it uses as much as digits as its factorization.
21433143000241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122268.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 21433143000241 its reverse (14200034133412), we get a palindrome (35633177133653).
The spelling of 21433143000241 in words is "twenty-one trillion, four hundred thirty-three billion, one hundred forty-three million, two hundred forty-one", and thus it is an aban number.
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