Base | Representation |
---|---|
bin | 11111001100001001000… |
… | …101110111100110000001 |
3 | 21120220100010121222202221 |
4 | 133030021011313212001 |
5 | 240104030322322311 |
6 | 4320345400411041 |
7 | 310564664502214 |
oct | 37141105674601 |
9 | 7526303558687 |
10 | 2143341214081 |
11 | 756a93269581 |
12 | 2a7488776a81 |
13 | 127168408a02 |
14 | 75a49b4577b |
15 | 3ab471e3671 |
hex | 1f309177981 |
2143341214081 has 2 divisors, whose sum is σ = 2143341214082. Its totient is φ = 2143341214080.
The previous prime is 2143341213983. The next prime is 2143341214109. The reversal of 2143341214081 is 1804121433412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1725755142400 + 417586071681 = 1313680^2 + 646209^2 .
It is a cyclic number.
It is not a de Polignac number, because 2143341214081 - 29 = 2143341213569 is a prime.
It is a super-3 number, since 3×21433412140813 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2143341214181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071670607040 + 1071670607041.
It is an arithmetic number, because the mean of its divisors is an integer number (1071670607041).
Almost surely, 22143341214081 is an apocalyptic number.
It is an amenable number.
2143341214081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143341214081 is an equidigital number, since it uses as much as digits as its factorization.
2143341214081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 34.
Adding to 2143341214081 its reverse (1804121433412), we get a palindrome (3947462647493).
The spelling of 2143341214081 in words is "two trillion, one hundred forty-three billion, three hundred forty-one million, two hundred fourteen thousand, eighty-one".
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