Base | Representation |
---|---|
bin | 1100011110011101011… |
… | …1001001100101111001 |
3 | 202111020101010021210111 |
4 | 3013213113021211321 |
5 | 12002424230044001 |
6 | 242244130544321 |
7 | 21325264315450 |
oct | 3074727114571 |
9 | 674211107714 |
10 | 214335003001 |
11 | 82998581119 |
12 | 356584380a1 |
13 | 1729a163082 |
14 | a533c7db97 |
15 | 5896bcc851 |
hex | 31e75c9979 |
214335003001 has 48 divisors (see below), whose sum is σ = 263534144256. Its totient is φ = 170714824704.
The previous prime is 214335002993. The next prime is 214335003059. The reversal of 214335003001 is 100300533412.
It is not a de Polignac number, because 214335003001 - 23 = 214335002993 is a prime.
It is a super-2 number, since 2×2143350030012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214335003101) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 53488140 + ... + 53492146.
It is an arithmetic number, because the mean of its divisors is an integer number (5490294672).
Almost surely, 2214335003001 is an apocalyptic number.
It is an amenable number.
214335003001 is a deficient number, since it is larger than the sum of its proper divisors (49199141255).
214335003001 is a wasteful number, since it uses less digits than its factorization.
214335003001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4378 (or 4361 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 214335003001 its reverse (100300533412), we get a palindrome (314635536413).
The spelling of 214335003001 in words is "two hundred fourteen billion, three hundred thirty-five million, three thousand, one".
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