Base | Representation |
---|---|
bin | 1001101111110100100010… |
… | …10110100111111100000001 |
3 | 2210220002201222211000122011 |
4 | 10313322101112213330001 |
5 | 10302134444302342423 |
6 | 113330443154012521 |
7 | 4341402365034604 |
oct | 467722126477401 |
9 | 83802658730564 |
10 | 21434325434113 |
11 | 6914278a08a99 |
12 | 24a2148277141 |
13 | bc632c438b67 |
14 | 5415d953a33b |
15 | 272851729b0d |
hex | 137e915a7f01 |
21434325434113 has 4 divisors (see below), whose sum is σ = 21445930376640. Its totient is φ = 21422720491588.
The previous prime is 21434325434107. The next prime is 21434325434117. The reversal of 21434325434113 is 31143452343412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21434325434113 - 29 = 21434325433601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21434325434117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5802468493 + ... + 5802472186.
It is an arithmetic number, because the mean of its divisors is an integer number (5361482594160).
Almost surely, 221434325434113 is an apocalyptic number.
It is an amenable number.
21434325434113 is a deficient number, since it is larger than the sum of its proper divisors (11604942527).
21434325434113 is a wasteful number, since it uses less digits than its factorization.
21434325434113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11604942526.
The product of its digits is 414720, while the sum is 40.
Adding to 21434325434113 its reverse (31143452343412), we get a palindrome (52577777777525).
The spelling of 21434325434113 in words is "twenty-one trillion, four hundred thirty-four billion, three hundred twenty-five million, four hundred thirty-four thousand, one hundred thirteen".
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