2144012513153 has 4 divisors (see below), whose sum is σ = 2450300015040. Its totient is φ = 1837725011268.

The previous prime is 2144012513147. The next prime is 2144012513189. The reversal of 2144012513153 is 3513152104412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2144012513153 - 2¹⁰ = 2144012512129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2144012813153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153143750933 + ... + 153143750946.

It is an arithmetic number, because the mean of its divisors is an integer number (612575003760).

Almost surely, 2^{2144012513153} is an apocalyptic number.

It is an amenable number.

2144012513153 is a deficient number, since it is larger than the sum of its proper divisors (306287501887).

2144012513153 is an equidigital number, since it uses as much as digits as its factorization.

2144012513153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306287501886.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 2144012513153 its reverse (3513152104412), we get a palindrome (5657164617565).

The spelling of 2144012513153 in words is "two trillion, one hundred forty-four billion, twelve million, five hundred thirteen thousand, one hundred fifty-three".