Base | Representation |
---|---|
bin | 11111001100110011011… |
… | …010011010100010000111 |
3 | 21120222011121200012112121 |
4 | 133030303122122202013 |
5 | 240112004104240033 |
6 | 4320544043030411 |
7 | 310621405603615 |
oct | 37146332324207 |
9 | 7528147605477 |
10 | 2144051243143 |
11 | 757318038957 |
12 | 2a764650b407 |
13 | 12724c549c54 |
14 | 75ab61706b5 |
15 | 3ab896e762d |
hex | 1f33369a887 |
2144051243143 has 16 divisors (see below), whose sum is σ = 2181016031040. Its totient is φ = 2107284480000.
The previous prime is 2144051243129. The next prime is 2144051243153. The reversal of 2144051243143 is 3413421504412.
It is a cyclic number.
It is not a de Polignac number, because 2144051243143 - 233 = 2135461308551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2144051243099 and 2144051243108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2144051243153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30376393 + ... + 30446893.
It is an arithmetic number, because the mean of its divisors is an integer number (136313501940).
Almost surely, 22144051243143 is an apocalyptic number.
2144051243143 is a deficient number, since it is larger than the sum of its proper divisors (36964787897).
2144051243143 is an equidigital number, since it uses as much as digits as its factorization.
2144051243143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71898.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 2144051243143 its reverse (3413421504412), we get a palindrome (5557472747555).
The spelling of 2144051243143 in words is "two trillion, one hundred forty-four billion, fifty-one million, two hundred forty-three thousand, one hundred forty-three".
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