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2144051243143 = 7155776970501
BaseRepresentation
bin11111001100110011011…
…010011010100010000111
321120222011121200012112121
4133030303122122202013
5240112004104240033
64320544043030411
7310621405603615
oct37146332324207
97528147605477
102144051243143
11757318038957
122a764650b407
1312724c549c54
1475ab61706b5
153ab896e762d
hex1f33369a887

2144051243143 has 16 divisors (see below), whose sum is σ = 2181016031040. Its totient is φ = 2107284480000.

The previous prime is 2144051243129. The next prime is 2144051243153. The reversal of 2144051243143 is 3413421504412.

It is a cyclic number.

It is not a de Polignac number, because 2144051243143 - 233 = 2135461308551 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2144051243099 and 2144051243108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2144051243153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30376393 + ... + 30446893.

It is an arithmetic number, because the mean of its divisors is an integer number (136313501940).

Almost surely, 22144051243143 is an apocalyptic number.

2144051243143 is a deficient number, since it is larger than the sum of its proper divisors (36964787897).

2144051243143 is an equidigital number, since it uses as much as digits as its factorization.

2144051243143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71898.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 2144051243143 its reverse (3413421504412), we get a palindrome (5557472747555).

The spelling of 2144051243143 in words is "two trillion, one hundred forty-four billion, fifty-one million, two hundred forty-three thousand, one hundred forty-three".

Divisors: 1 71 557 769 39547 54599 70501 428333 5005571 30411643 39269057 54215269 2788103047 3849284099 30197904833 2144051243143