Base | Representation |
---|---|
bin | 11111001100111000110… |
… | …010110000111101100111 |
3 | 21120222101220112100220000 |
4 | 133030320302300331213 |
5 | 240112200211400201 |
6 | 4321001025512343 |
7 | 310623553101003 |
oct | 37147062607547 |
9 | 7528356470800 |
10 | 2144141512551 |
11 | 757363a93675 |
12 | 2a76707a26b3 |
13 | 1272651646bc |
14 | 75ac414b703 |
15 | 3ab925c8d86 |
hex | 1f338cb0f67 |
2144141512551 has 10 divisors (see below), whose sum is σ = 3202976827512. Its totient is φ = 1429427674980.
The previous prime is 2144141512489. The next prime is 2144141512553. The reversal of 2144141512551 is 1552151414412.
2144141512551 is a `hidden beast` number, since 2 + 1 + 44 + 14 + 1 + 51 + 2 + 551 = 666.
It is not a de Polignac number, because 2144141512551 - 211 = 2144141510503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2144141512553) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 13235441355 + ... + 13235441516.
Almost surely, 22144141512551 is an apocalyptic number.
2144141512551 is a deficient number, since it is larger than the sum of its proper divisors (1058835314961).
2144141512551 is an equidigital number, since it uses as much as digits as its factorization.
2144141512551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26470882883 (or 26470882874 counting only the distinct ones).
The product of its digits is 32000, while the sum is 36.
Adding to 2144141512551 its reverse (1552151414412), we get a palindrome (3696292926963).
The spelling of 2144141512551 in words is "two trillion, one hundred forty-four billion, one hundred forty-one million, five hundred twelve thousand, five hundred fifty-one".
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