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214441113 = 371480371
BaseRepresentation
bin11001100100000…
…01110010011001
3112221111201220110
430302001302121
5414344103423
633140114533
75212501515
oct1462016231
9487451813
10214441113
11100056867
125b995a49
1335572443
14206a1145
1513c5d193
hexcc81c99

214441113 has 4 divisors (see below), whose sum is σ = 285921488. Its totient is φ = 142960740.

The previous prime is 214441099. The next prime is 214441141. The reversal of 214441113 is 311144412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 214441113 - 25 = 214441081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 214441113.

It is not an unprimeable number, because it can be changed into a prime (214441153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35740183 + ... + 35740188.

It is an arithmetic number, because the mean of its divisors is an integer number (71480372).

Almost surely, 2214441113 is an apocalyptic number.

It is an amenable number.

214441113 is a deficient number, since it is larger than the sum of its proper divisors (71480375).

214441113 is an equidigital number, since it uses as much as digits as its factorization.

214441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71480374.

The product of its digits is 384, while the sum is 21.

The square root of 214441113 is about 14643.8080088480. The cubic root of 214441113 is about 598.5530997151.

Adding to 214441113 its reverse (311144412), we get a palindrome (525585525).

The spelling of 214441113 in words is "two hundred fourteen million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 3 71480371 214441113