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2145242413131 = 31258356829119
BaseRepresentation
bin11111001101111010011…
…010010111100001001011
321121002020122001220120120
4133031322122113201023
5240121424024210011
64321302153554323
7310663051434456
oct37157232274113
97532218056516
102145242413131
11757879463564
122a79194159a3
131273ac26c26c
1475b8a44249d
153ac0908ba06
hex1f37a69784b

2145242413131 has 8 divisors (see below), whose sum is σ = 2860550584320. Its totient is φ = 1430047925352.

The previous prime is 2145242413121. The next prime is 2145242413133. The reversal of 2145242413131 is 1313142425412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2145242413131 - 25 = 2145242413099 is a prime.

It is a super-2 number, since 2×21452424131312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2145242413092 and 2145242413101.

It is not an unprimeable number, because it can be changed into a prime (2145242413133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28376811 + ... + 28452308.

It is an arithmetic number, because the mean of its divisors is an integer number (357568823040).

Almost surely, 22145242413131 is an apocalyptic number.

2145242413131 is a deficient number, since it is larger than the sum of its proper divisors (715308171189).

2145242413131 is a wasteful number, since it uses less digits than its factorization.

2145242413131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56841705.

The product of its digits is 23040, while the sum is 33.

Adding to 2145242413131 its reverse (1313142425412), we get a palindrome (3458384838543).

The spelling of 2145242413131 in words is "two trillion, one hundred forty-five billion, two hundred forty-two million, four hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 12583 37749 56829119 170487357 715080804377 2145242413131