Base | Representation |
---|---|
bin | 11111001110000000010… |
… | …010111100011000000011 |
3 | 21121002111111211020222220 |
4 | 133032000102330120003 |
5 | 240122124312131433 |
6 | 4321320041502123 |
7 | 310665360504453 |
oct | 37160022743003 |
9 | 7532444736886 |
10 | 2145341130243 |
11 | 75791a159153 |
12 | 2a79464a1943 |
13 | 1273c6853b5c |
14 | 75b995bbd63 |
15 | 3ac12a8b2b3 |
hex | 1f3804bc603 |
2145341130243 has 4 divisors (see below), whose sum is σ = 2860454840328. Its totient is φ = 1430227420160.
The previous prime is 2145341130211. The next prime is 2145341130263. The reversal of 2145341130243 is 3420311435412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2145341130243 - 25 = 2145341130211 is a prime.
It is a super-2 number, since 2×21453411302432 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2145341130263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357556855038 + ... + 357556855043.
It is an arithmetic number, because the mean of its divisors is an integer number (715113710082).
Almost surely, 22145341130243 is an apocalyptic number.
2145341130243 is a deficient number, since it is larger than the sum of its proper divisors (715113710085).
2145341130243 is an equidigital number, since it uses as much as digits as its factorization.
2145341130243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 715113710084.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 2145341130243 its reverse (3420311435412), we get a palindrome (5565652565655).
The spelling of 2145341130243 in words is "two trillion, one hundred forty-five billion, three hundred forty-one million, one hundred thirty thousand, two hundred forty-three".
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