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2145341130243 = 3715113710081
BaseRepresentation
bin11111001110000000010…
…010111100011000000011
321121002111111211020222220
4133032000102330120003
5240122124312131433
64321320041502123
7310665360504453
oct37160022743003
97532444736886
102145341130243
1175791a159153
122a79464a1943
131273c6853b5c
1475b995bbd63
153ac12a8b2b3
hex1f3804bc603

2145341130243 has 4 divisors (see below), whose sum is σ = 2860454840328. Its totient is φ = 1430227420160.

The previous prime is 2145341130211. The next prime is 2145341130263. The reversal of 2145341130243 is 3420311435412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2145341130243 - 25 = 2145341130211 is a prime.

It is a super-2 number, since 2×21453411302432 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2145341130263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357556855038 + ... + 357556855043.

It is an arithmetic number, because the mean of its divisors is an integer number (715113710082).

Almost surely, 22145341130243 is an apocalyptic number.

2145341130243 is a deficient number, since it is larger than the sum of its proper divisors (715113710085).

2145341130243 is an equidigital number, since it uses as much as digits as its factorization.

2145341130243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715113710084.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 2145341130243 its reverse (3420311435412), we get a palindrome (5565652565655).

The spelling of 2145341130243 in words is "two trillion, one hundred forty-five billion, three hundred forty-one million, one hundred thirty thousand, two hundred forty-three".

Divisors: 1 3 715113710081 2145341130243