Base | Representation |
---|---|
bin | 1100011111001101000… |
… | …0001111110101110001 |
3 | 202111202021112210220112 |
4 | 3013303100033311301 |
5 | 12003331314121202 |
6 | 242320015151105 |
7 | 21333236222255 |
oct | 3076320176561 |
9 | 674667483815 |
10 | 214534520177 |
11 | 82a9016434a |
12 | 356b3215495 |
13 | 172cc5ab683 |
14 | a552578265 |
15 | 58a948db52 |
hex | 31f340fd71 |
214534520177 has 2 divisors, whose sum is σ = 214534520178. Its totient is φ = 214534520176.
The previous prime is 214534520119. The next prime is 214534520191. The reversal of 214534520177 is 771025435412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 212225141041 + 2309379136 = 460679^2 + 48056^2 .
It is a cyclic number.
It is not a de Polignac number, because 214534520177 - 210 = 214534519153 is a prime.
It is a super-2 number, since 2×2145345201772 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (214534520107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107267260088 + 107267260089.
It is an arithmetic number, because the mean of its divisors is an integer number (107267260089).
Almost surely, 2214534520177 is an apocalyptic number.
It is an amenable number.
214534520177 is a deficient number, since it is larger than the sum of its proper divisors (1).
214534520177 is an equidigital number, since it uses as much as digits as its factorization.
214534520177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 235200, while the sum is 41.
Adding to 214534520177 its reverse (771025435412), we get a palindrome (985559955589).
The spelling of 214534520177 in words is "two hundred fourteen billion, five hundred thirty-four million, five hundred twenty thousand, one hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •