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2145353041411 = 19112913317969
BaseRepresentation
bin11111001110000001000…
…000011000011000000011
321121002112100020102001021
4133032001000120120003
5240122140334311121
64321321145050311
7310665563654056
oct37160100303003
97532470212037
102145353041411
11757925954198
122a794a486997
131273c9164598
1475b9addca9d
153ac13b40641
hex1f381018603

2145353041411 has 4 divisors (see below), whose sum is σ = 2258266359400. Its totient is φ = 2032439723424.

The previous prime is 2145353041379. The next prime is 2145353041423. The reversal of 2145353041411 is 1141403535412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2145353041411 - 25 = 2145353041379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2145353045411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56456658966 + ... + 56456659003.

It is an arithmetic number, because the mean of its divisors is an integer number (564566589850).

Almost surely, 22145353041411 is an apocalyptic number.

2145353041411 is a deficient number, since it is larger than the sum of its proper divisors (112913317989).

2145353041411 is a wasteful number, since it uses less digits than its factorization.

2145353041411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112913317988.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 2145353041411 its reverse (1141403535412), we get a palindrome (3286756576823).

The spelling of 2145353041411 in words is "two trillion, one hundred forty-five billion, three hundred fifty-three million, forty-one thousand, four hundred eleven".

Divisors: 1 19 112913317969 2145353041411