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2145554400401 = 3169211432271
BaseRepresentation
bin11111001110001101000…
…000100000010010010001
321121010001101010111122122
4133032031000200102101
5240123043411303101
64321353140544025
7311003560331366
oct37161500402221
97533041114578
102145554400401
11757a19585185
122a79a59b2015
1312742baa6309
1475bb9a5646d
153ac2666751b
hex1f38d020491

2145554400401 has 4 divisors (see below), whose sum is σ = 2214765832704. Its totient is φ = 2076342968100.

The previous prime is 2145554400373. The next prime is 2145554400403. The reversal of 2145554400401 is 1040044555412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2145554400401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2145554400403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34605716105 + ... + 34605716166.

It is an arithmetic number, because the mean of its divisors is an integer number (553691458176).

Almost surely, 22145554400401 is an apocalyptic number.

It is an amenable number.

2145554400401 is a deficient number, since it is larger than the sum of its proper divisors (69211432303).

2145554400401 is an equidigital number, since it uses as much as digits as its factorization.

2145554400401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69211432302.

The product of its (nonzero) digits is 64000, while the sum is 35.

Adding to 2145554400401 its reverse (1040044555412), we get a palindrome (3185598955813).

The spelling of 2145554400401 in words is "two trillion, one hundred forty-five billion, five hundred fifty-four million, four hundred thousand, four hundred one".

Divisors: 1 31 69211432271 2145554400401