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2146312000153 = 13191627226687
BaseRepresentation
bin11111001110111010001…
…010100001001010011001
321121012000011200120010201
4133032322022201022121
5240131121333001103
64322000242542201
7311031416662126
oct37167212411231
97535004616121
102146312000153
11758278196082
122a7b77667961
1312751ca31ca9
1475c4c50574d
153ac6ce1651d
hex1f3ba2a1299

2146312000153 has 4 divisors (see below), whose sum is σ = 2147939228160. Its totient is φ = 2144684772148.

The previous prime is 2146312000099. The next prime is 2146312000187. The reversal of 2146312000153 is 3510002136412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2146312000153 - 29 = 2146311999641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2146312000193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 813612025 + ... + 813614662.

It is an arithmetic number, because the mean of its divisors is an integer number (536984807040).

Almost surely, 22146312000153 is an apocalyptic number.

It is an amenable number.

2146312000153 is a deficient number, since it is larger than the sum of its proper divisors (1627228007).

2146312000153 is a wasteful number, since it uses less digits than its factorization.

2146312000153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1627228006.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 2146312000153 its reverse (3510002136412), we get a palindrome (5656314136565).

The spelling of 2146312000153 in words is "two trillion, one hundred forty-six billion, three hundred twelve million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 1319 1627226687 2146312000153