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21471120257 is a prime number
BaseRepresentation
bin10011111111110001…
…110100101110000001
32001102100200220212012
4103333301310232001
5322433101322012
613510320342305
71360034340146
oct237761645601
961370626765
1021471120257
119118984494
1241b2774995
1320423c7ab2
14107982c3cd
15859ead622
hex4ffc74b81

21471120257 has 2 divisors, whose sum is σ = 21471120258. Its totient is φ = 21471120256.

The previous prime is 21471120191. The next prime is 21471120277. The reversal of 21471120257 is 75202117412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17981737216 + 3489383041 = 134096^2 + 59071^2 .

It is a cyclic number.

It is not a de Polignac number, because 21471120257 - 28 = 21471120001 is a prime.

It is a super-2 number, since 2×214711202572 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21471120277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10735560128 + 10735560129.

It is an arithmetic number, because the mean of its divisors is an integer number (10735560129).

Almost surely, 221471120257 is an apocalyptic number.

It is an amenable number.

21471120257 is a deficient number, since it is larger than the sum of its proper divisors (1).

21471120257 is an equidigital number, since it uses as much as digits as its factorization.

21471120257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7840, while the sum is 32.

Adding to 21471120257 its reverse (75202117412), we get a palindrome (96673237669).

The spelling of 21471120257 in words is "twenty-one billion, four hundred seventy-one million, one hundred twenty thousand, two hundred fifty-seven".