Base | Representation |
---|---|
bin | 1001110000111010001011… |
… | …01111111011010100011011 |
3 | 2211000200020111200022221111 |
4 | 10320131011233323110123 |
5 | 10303243031144014342 |
6 | 113355545043321151 |
7 | 4344165014062162 |
oct | 470350557732433 |
9 | 84020214608844 |
10 | 21471711704347 |
11 | 6929113544193 |
12 | 24a94409801b7 |
13 | bc9a09b4c058 |
14 | 5433449303d9 |
15 | 2737dda1d217 |
hex | 138745bfb51b |
21471711704347 has 2 divisors, whose sum is σ = 21471711704348. Its totient is φ = 21471711704346.
The previous prime is 21471711704341. The next prime is 21471711704351. The reversal of 21471711704347 is 74340711717412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21471711704347 - 211 = 21471711702299 is a prime.
It is a super-2 number, since 2×214717117043472 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21471711704347.
It is not a weakly prime, because it can be changed into another prime (21471711704341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10735855852173 + 10735855852174.
It is an arithmetic number, because the mean of its divisors is an integer number (10735855852174).
Almost surely, 221471711704347 is an apocalyptic number.
21471711704347 is a deficient number, since it is larger than the sum of its proper divisors (1).
21471711704347 is an equidigital number, since it uses as much as digits as its factorization.
21471711704347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 921984, while the sum is 49.
The spelling of 21471711704347 in words is "twenty-one trillion, four hundred seventy-one billion, seven hundred eleven million, seven hundred four thousand, three hundred forty-seven".
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