Base | Representation |
---|---|
bin | 11111010000110011111… |
… | …101111111010011000001 |
3 | 21121101021120221221101222 |
4 | 133100303331333103001 |
5 | 240144313004123230 |
6 | 4322535123004425 |
7 | 311133152516564 |
oct | 37206375772301 |
9 | 7541246857358 |
10 | 2148355536065 |
11 | 759126768932 |
12 | 2a8447b09715 |
13 | 12778721043b |
14 | 75da3a944db |
15 | 3ad3c5286e5 |
hex | 1f433f7f4c1 |
2148355536065 has 16 divisors (see below), whose sum is σ = 2592942166080. Its totient is φ = 1708744549440.
The previous prime is 2148355536007. The next prime is 2148355536113. The reversal of 2148355536065 is 5606355538412.
It is not a de Polignac number, because 2148355536065 - 26 = 2148355536001 is a prime.
It is a super-2 number, since 2×21483555360652 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2148355535998 and 2148355536016.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4335755 + ... + 4805775.
It is an arithmetic number, because the mean of its divisors is an integer number (162058885380).
Almost surely, 22148355536065 is an apocalyptic number.
It is an amenable number.
2148355536065 is a deficient number, since it is larger than the sum of its proper divisors (444586630015).
2148355536065 is a wasteful number, since it uses less digits than its factorization.
2148355536065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 475312.
The product of its (nonzero) digits is 12960000, while the sum is 53.
The spelling of 2148355536065 in words is "two trillion, one hundred forty-eight billion, three hundred fifty-five million, five hundred thirty-six thousand, sixty-five".
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