Base | Representation |
---|---|
bin | 11111010001100000110… |
… | …000111100101001101011 |
3 | 21121110012222010221102202 |
4 | 133101200300330221223 |
5 | 240202332403421300 |
6 | 4323141451250415 |
7 | 311160606606146 |
oct | 37214060745153 |
9 | 7543188127382 |
10 | 2149107092075 |
11 | 759481a20aa9 |
12 | 2a8617749a0b |
13 | 127876b31238 |
14 | 7603580d05d |
15 | 3ad834d1ad5 |
hex | 1f460c3ca6b |
2149107092075 has 6 divisors (see below), whose sum is σ = 2664892794204. Its totient is φ = 1719285673640.
The previous prime is 2149107092071. The next prime is 2149107092137. The reversal of 2149107092075 is 5702907019412.
It is not a de Polignac number, because 2149107092075 - 22 = 2149107092071 is a prime.
It is a super-2 number, since 2×21491070920752 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2149107092071) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 42982141817 + ... + 42982141866.
It is an arithmetic number, because the mean of its divisors is an integer number (444148799034).
Almost surely, 22149107092075 is an apocalyptic number.
2149107092075 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2149107092075 is a deficient number, since it is larger than the sum of its proper divisors (515785702129).
2149107092075 is an equidigital number, since it uses as much as digits as its factorization.
2149107092075 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85964283693 (or 85964283688 counting only the distinct ones).
The product of its (nonzero) digits is 317520, while the sum is 47.
The spelling of 2149107092075 in words is "two trillion, one hundred forty-nine billion, one hundred seven million, ninety-two thousand, seventy-five".
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