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214930503 = 3416715889
BaseRepresentation
bin11001100111110…
…01010001000111
3112222102121020000
430303321101013
5420010234003
633154412343
75216610354
oct1463712107
9488377200
10214930503
11100360517
125bb910b3
13356b4118
142078b62b
1513d081a3
hexccf9447

214930503 has 20 divisors (see below), whose sum is σ = 323011920. Its totient is φ = 142420032.

The previous prime is 214930501. The next prime is 214930519. The reversal of 214930503 is 305039412.

It is not a de Polignac number, because 214930503 - 21 = 214930501 is a prime.

It is a super-2 number, since 2×2149305032 = 92390242239666018, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214930501) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 5583 + ... + 21471.

It is an arithmetic number, because the mean of its divisors is an integer number (16150596).

Almost surely, 2214930503 is an apocalyptic number.

214930503 is a deficient number, since it is larger than the sum of its proper divisors (108081417).

214930503 is a wasteful number, since it uses less digits than its factorization.

214930503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16068 (or 16059 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

The square root of 214930503 is about 14660.5082790468. The cubic root of 214930503 is about 599.0080860816.

Adding to 214930503 its reverse (305039412), we get a palindrome (519969915).

The spelling of 214930503 in words is "two hundred fourteen million, nine hundred thirty thousand, five hundred three".

Divisors: 1 3 9 27 81 167 501 1503 4509 13527 15889 47667 143001 429003 1287009 2653463 7960389 23881167 71643501 214930503