Base | Representation |
---|---|
bin | 10100000001011110… |
… | …000101001111001011 |
3 | 2001111100002201211001 |
4 | 110001132011033023 |
5 | 323012332440332 |
6 | 13513212515431 |
7 | 1360530505315 |
oct | 240136051713 |
9 | 61440081731 |
10 | 21499499467 |
11 | 91329a8186 |
12 | 420017bb77 |
13 | 2048253124 |
14 | 107d4d87b5 |
15 | 85c7170e7 |
hex | 5017853cb |
21499499467 has 2 divisors, whose sum is σ = 21499499468. Its totient is φ = 21499499466.
The previous prime is 21499499453. The next prime is 21499499543. The reversal of 21499499467 is 76499499412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21499499467 - 211 = 21499497419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21499499399 and 21499499408.
It is not a weakly prime, because it can be changed into another prime (21499499447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10749749733 + 10749749734.
It is an arithmetic number, because the mean of its divisors is an integer number (10749749734).
Almost surely, 221499499467 is an apocalyptic number.
21499499467 is a deficient number, since it is larger than the sum of its proper divisors (1).
21499499467 is an equidigital number, since it uses as much as digits as its factorization.
21499499467 is an evil number, because the sum of its binary digits is even.
The product of its digits is 35271936, while the sum is 64.
Subtracting 21499499467 from its reverse (76499499412), we obtain a palindrome (54999999945).
The spelling of 21499499467 in words is "twenty-one billion, four hundred ninety-nine million, four hundred ninety-nine thousand, four hundred sixty-seven".
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