Base | Representation |
---|---|
bin | 1001110001110000110011… |
… | …00011100101001011101001 |
3 | 2211010110221002201012102011 |
4 | 10320320121203211023221 |
5 | 10304233104432312023 |
6 | 113421234504235521 |
7 | 4346253456245116 |
oct | 470703143451351 |
9 | 84113832635364 |
10 | 21501035041513 |
11 | 693a5a0828435 |
12 | 24b306516bba1 |
13 | bcc700c86131 |
14 | 54492715790d |
15 | 27445803450d |
hex | 138e198e52e9 |
21501035041513 has 2 divisors, whose sum is σ = 21501035041514. Its totient is φ = 21501035041512.
The previous prime is 21501035041489. The next prime is 21501035041517. The reversal of 21501035041513 is 31514053010512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19038797042409 + 2462237999104 = 4363347^2 + 1569152^2 .
It is a cyclic number.
It is not a de Polignac number, because 21501035041513 - 25 = 21501035041481 is a prime.
It is not a weakly prime, because it can be changed into another prime (21501035041517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10750517520756 + 10750517520757.
It is an arithmetic number, because the mean of its divisors is an integer number (10750517520757).
Almost surely, 221501035041513 is an apocalyptic number.
It is an amenable number.
21501035041513 is a deficient number, since it is larger than the sum of its proper divisors (1).
21501035041513 is an equidigital number, since it uses as much as digits as its factorization.
21501035041513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 21501035041513 in words is "twenty-one trillion, five hundred one billion, thirty-five million, forty-one thousand, five hundred thirteen".
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