Base | Representation |
---|---|
bin | 11111010010011100011… |
… | …000111010100111010001 |
3 | 21121112210200110010112222 |
4 | 133102130120322213101 |
5 | 240211410000101413 |
6 | 4323425024030425 |
7 | 311224444365305 |
oct | 37223430724721 |
9 | 7545720403488 |
10 | 2150107425233 |
11 | 759945652119 |
12 | 2a8856762415 |
13 | 1279a6156c51 |
14 | 760cc605d05 |
15 | 3ade122bb08 |
hex | 1f49c63a9d1 |
2150107425233 has 2 divisors, whose sum is σ = 2150107425234. Its totient is φ = 2150107425232.
The previous prime is 2150107425211. The next prime is 2150107425253. The reversal of 2150107425233 is 3325247010512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1684523643664 + 465583781569 = 1297892^2 + 682337^2 .
It is a cyclic number.
It is not a de Polignac number, because 2150107425233 - 240 = 1050595797457 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2150107425193 and 2150107425202.
It is not a weakly prime, because it can be changed into another prime (2150107425253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075053712616 + 1075053712617.
It is an arithmetic number, because the mean of its divisors is an integer number (1075053712617).
Almost surely, 22150107425233 is an apocalyptic number.
It is an amenable number.
2150107425233 is a deficient number, since it is larger than the sum of its proper divisors (1).
2150107425233 is an equidigital number, since it uses as much as digits as its factorization.
2150107425233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 2150107425233 in words is "two trillion, one hundred fifty billion, one hundred seven million, four hundred twenty-five thousand, two hundred thirty-three".
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