Base | Representation |
---|---|
bin | 11111010011011010111… |
… | …010101100000110000011 |
3 | 21121122111210101221000121 |
4 | 133103122322230012003 |
5 | 240221032023403201 |
6 | 4324121100401111 |
7 | 311262443160325 |
oct | 37233272540603 |
9 | 7548453357017 |
10 | 2151156466051 |
11 | 75a333820aaa |
12 | 2a8aa9b46197 |
13 | 127b125a4a68 |
14 | 7618ba7b615 |
15 | 3ae533989a1 |
hex | 1f4daeac183 |
2151156466051 has 2 divisors, whose sum is σ = 2151156466052. Its totient is φ = 2151156466050.
The previous prime is 2151156466027. The next prime is 2151156466073. The reversal of 2151156466051 is 1506646511512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2151156466051 - 221 = 2151154368899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2151156465989 and 2151156466007.
It is not a weakly prime, because it can be changed into another prime (2151156466001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075578233025 + 1075578233026.
It is an arithmetic number, because the mean of its divisors is an integer number (1075578233026).
Almost surely, 22151156466051 is an apocalyptic number.
2151156466051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151156466051 is an equidigital number, since it uses as much as digits as its factorization.
2151156466051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 43.
The spelling of 2151156466051 in words is "two trillion, one hundred fifty-one billion, one hundred fifty-six million, four hundred sixty-six thousand, fifty-one".
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