Base | Representation |
---|---|
bin | 11111010011011110010… |
… | …011001001101101010011 |
3 | 21121122122202011211201001 |
4 | 133103132103021231103 |
5 | 240221141040213301 |
6 | 4324130444522431 |
7 | 311264032405024 |
oct | 37233623115523 |
9 | 7548582154631 |
10 | 2151213210451 |
11 | 75a3628589a8 |
12 | 2a8b04b50417 |
13 | 127b21281c26 |
14 | 7619540cc4b |
15 | 3ae58356c01 |
hex | 1f4de4c9b53 |
2151213210451 has 2 divisors, whose sum is σ = 2151213210452. Its totient is φ = 2151213210450.
The previous prime is 2151213210431. The next prime is 2151213210547. The reversal of 2151213210451 is 1540123121512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2151213210451 - 219 = 2151212686163 is a prime.
It is not a weakly prime, because it can be changed into another prime (2151213210431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075606605225 + 1075606605226.
It is an arithmetic number, because the mean of its divisors is an integer number (1075606605226).
Almost surely, 22151213210451 is an apocalyptic number.
2151213210451 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151213210451 is an equidigital number, since it uses as much as digits as its factorization.
2151213210451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 2151213210451 its reverse (1540123121512), we get a palindrome (3691336331963).
The spelling of 2151213210451 in words is "two trillion, one hundred fifty-one billion, two hundred thirteen million, two hundred ten thousand, four hundred fifty-one".
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