Base | Representation |
---|---|
bin | 1001110010000110001101… |
… | …10101000010100001101010 |
3 | 2211011120121100021202210002 |
4 | 10321003012311002201222 |
5 | 10304430131143323424 |
6 | 113430415404223002 |
7 | 4350141412003664 |
oct | 471030665024152 |
9 | 84146540252702 |
10 | 21512532011114 |
11 | 6944460542901 |
12 | 24b533353aa62 |
13 | c00813b44421 |
14 | 5452d8031534 |
15 | 2748cc53dcae |
hex | 1390c6d4286a |
21512532011114 has 8 divisors (see below), whose sum is σ = 32455322861220. Its totient is φ = 10694091057376.
The previous prime is 21512532011059. The next prime is 21512532011149. The reversal of 21512532011114 is 41111023521512.
It can be written as a sum of positive squares in 2 ways, for example, as 20865847447225 + 646684563889 = 4567915^2 + 804167^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×215125320111142 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31087473659 + ... + 31087474350.
Almost surely, 221512532011114 is an apocalyptic number.
21512532011114 is a deficient number, since it is larger than the sum of its proper divisors (10942790850106).
21512532011114 is a wasteful number, since it uses less digits than its factorization.
21512532011114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62174948184.
The product of its (nonzero) digits is 2400, while the sum is 29.
Adding to 21512532011114 its reverse (41111023521512), we get a palindrome (62623555532626).
The spelling of 21512532011114 in words is "twenty-one trillion, five hundred twelve billion, five hundred thirty-two million, eleven thousand, one hundred fourteen".
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