Base | Representation |
---|---|
bin | 11111010011100010010… |
… | …110111001101101111001 |
3 | 21121122211111022021021211 |
4 | 133103202112321231321 |
5 | 240221311003134033 |
6 | 4324141320203121 |
7 | 311265520233556 |
oct | 37234226715571 |
9 | 7548744267254 |
10 | 2151281302393 |
11 | 75a398236433 |
12 | 2a8b239094a1 |
13 | 127b32403112 |
14 | 761a0495a2d |
15 | 3ae5e3072cd |
hex | 1f4e25b9b79 |
2151281302393 has 2 divisors, whose sum is σ = 2151281302394. Its totient is φ = 2151281302392.
The previous prime is 2151281302369. The next prime is 2151281302397. The reversal of 2151281302393 is 3932031821512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2065463357584 + 85817944809 = 1437172^2 + 292947^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151281302393 - 217 = 2151281171321 is a prime.
It is a super-2 number, since 2×21512813023932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2151281302397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075640651196 + 1075640651197.
It is an arithmetic number, because the mean of its divisors is an integer number (1075640651197).
Almost surely, 22151281302393 is an apocalyptic number.
It is an amenable number.
2151281302393 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151281302393 is an equidigital number, since it uses as much as digits as its factorization.
2151281302393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 2151281302393 in words is "two trillion, one hundred fifty-one billion, two hundred eighty-one million, three hundred two thousand, three hundred ninety-three".
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