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21513003435211 is a prime number
BaseRepresentation
bin1001110010000111000101…
…11011011000010011001011
32211011121211012100121001211
410321003202323120103023
510304432112334411321
6113430534244353551
74350156165023161
oct471034273302313
984147735317054
1021513003435211
1169446826617a2
1224b54453a58b7
13c0088a7027b2
145453408a9231
15274908b100e1
hex1390e2ed84cb

21513003435211 has 2 divisors, whose sum is σ = 21513003435212. Its totient is φ = 21513003435210.

The previous prime is 21513003435127. The next prime is 21513003435223. The reversal of 21513003435211 is 11253430031512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21513003435211 - 219 = 21513002910923 is a prime.

It is a super-2 number, since 2×215130034352112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21513003435251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756501717605 + 10756501717606.

It is an arithmetic number, because the mean of its divisors is an integer number (10756501717606).

Almost surely, 221513003435211 is an apocalyptic number.

21513003435211 is a deficient number, since it is larger than the sum of its proper divisors (1).

21513003435211 is an equidigital number, since it uses as much as digits as its factorization.

21513003435211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 21513003435211 its reverse (11253430031512), we get a palindrome (32766433466723).

The spelling of 21513003435211 in words is "twenty-one trillion, five hundred thirteen billion, three million, four hundred thirty-five thousand, two hundred eleven".