Base | Representation |
---|---|
bin | 1001110010000111000101… |
… | …11011011000010011001011 |
3 | 2211011121211012100121001211 |
4 | 10321003202323120103023 |
5 | 10304432112334411321 |
6 | 113430534244353551 |
7 | 4350156165023161 |
oct | 471034273302313 |
9 | 84147735317054 |
10 | 21513003435211 |
11 | 69446826617a2 |
12 | 24b54453a58b7 |
13 | c0088a7027b2 |
14 | 5453408a9231 |
15 | 274908b100e1 |
hex | 1390e2ed84cb |
21513003435211 has 2 divisors, whose sum is σ = 21513003435212. Its totient is φ = 21513003435210.
The previous prime is 21513003435127. The next prime is 21513003435223. The reversal of 21513003435211 is 11253430031512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21513003435211 - 219 = 21513002910923 is a prime.
It is a super-2 number, since 2×215130034352112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21513003435251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756501717605 + 10756501717606.
It is an arithmetic number, because the mean of its divisors is an integer number (10756501717606).
Almost surely, 221513003435211 is an apocalyptic number.
21513003435211 is a deficient number, since it is larger than the sum of its proper divisors (1).
21513003435211 is an equidigital number, since it uses as much as digits as its factorization.
21513003435211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 21513003435211 its reverse (11253430031512), we get a palindrome (32766433466723).
The spelling of 21513003435211 in words is "twenty-one trillion, five hundred thirteen billion, three million, four hundred thirty-five thousand, two hundred eleven".
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