Base | Representation |
---|---|
bin | 110000111010100110101001… |
… | …110001111111000111110011 |
3 | 1001012201120002002120022121111 |
4 | 300322212221301333013303 |
5 | 211144221314111424301 |
6 | 2041314541040334151 |
7 | 63212610552303655 |
oct | 6072465161770763 |
9 | 1035646062508544 |
10 | 215133465342451 |
11 | 62603654739037 |
12 | 20166382314357 |
13 | 9306cca2a6876 |
14 | 3b1a72dd006d5 |
15 | 19d11ad8ca551 |
hex | c3a9a9c7f1f3 |
215133465342451 has 4 divisors (see below), whose sum is σ = 215376005890512. Its totient is φ = 214890924794392.
The previous prime is 215133465342371. The next prime is 215133465342461. The reversal of 215133465342451 is 154243564331512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215133465342451 - 225 = 215133431788019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215133465342395 and 215133465342404.
It is not an unprimeable number, because it can be changed into a prime (215133465342461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121270272700 + ... + 121270274473.
It is an arithmetic number, because the mean of its divisors is an integer number (53844001472628).
Almost surely, 2215133465342451 is an apocalyptic number.
215133465342451 is a deficient number, since it is larger than the sum of its proper divisors (242540548061).
215133465342451 is an equidigital number, since it uses as much as digits as its factorization.
215133465342451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242540548060.
The product of its digits is 5184000, while the sum is 49.
The spelling of 215133465342451 in words is "two hundred fifteen trillion, one hundred thirty-three billion, four hundred sixty-five million, three hundred forty-two thousand, four hundred fifty-one".
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