Search a number
-
+
2151350497 is a prime number
BaseRepresentation
bin1000000000111011…
…0000000011100001
312112221010221002001
42000032300003201
513401221203442
6553250524001
7104212114612
oct20016600341
95487127061
102151350497
11a0442151a
12500596601
13283929b7a
14165a15c09
15c8d0c2b7
hex803b00e1

2151350497 has 2 divisors, whose sum is σ = 2151350498. Its totient is φ = 2151350496.

The previous prime is 2151350491. The next prime is 2151350519. The reversal of 2151350497 is 7940531512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1490654881 + 660695616 = 38609^2 + 25704^2 .

It is a cyclic number.

It is not a de Polignac number, because 2151350497 - 211 = 2151348449 is a prime.

It is not a weakly prime, because it can be changed into another prime (2151350491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075675248 + 1075675249.

It is an arithmetic number, because the mean of its divisors is an integer number (1075675249).

Almost surely, 22151350497 is an apocalyptic number.

It is an amenable number.

2151350497 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151350497 is an equidigital number, since it uses as much as digits as its factorization.

2151350497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 37.

The square root of 2151350497 is about 46382.6529750078. The cubic root of 2151350497 is about 1290.9330623050.

It can be divided in two parts, 21513 and 50497, that added together give a triangular number (72010 = T379).

The spelling of 2151350497 in words is "two billion, one hundred fifty-one million, three hundred fifty thousand, four hundred ninety-seven".