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215140030555433 is a prime number
BaseRepresentation
bin110000111010101100110001…
…000110010010010100101001
31001012202012000122011200201212
4300322230301012102110221
5211144323240310233213
62041321544323522505
763213232341554414
oct6072546106222451
91035665018150655
10215140030555433
1162606413617795
12201676b4b29435
1393078054ab389
143b1ab93bdcb7b
1519d1444e5d9a8
hexc3ab31192529

215140030555433 has 2 divisors, whose sum is σ = 215140030555434. Its totient is φ = 215140030555432.

The previous prime is 215140030555361. The next prime is 215140030555451. The reversal of 215140030555433 is 334555030041512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195394911727129 + 19745118828304 = 13978373^2 + 4443548^2 .

It is a cyclic number.

It is not a de Polignac number, because 215140030555433 - 218 = 215140030293289 is a prime.

It is not a weakly prime, because it can be changed into another prime (215140030558433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107570015277716 + 107570015277717.

It is an arithmetic number, because the mean of its divisors is an integer number (107570015277717).

Almost surely, 2215140030555433 is an apocalyptic number.

It is an amenable number.

215140030555433 is a deficient number, since it is larger than the sum of its proper divisors (1).

215140030555433 is an equidigital number, since it uses as much as digits as its factorization.

215140030555433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 215140030555433 its reverse (334555030041512), we get a palindrome (549695060596945).

The spelling of 215140030555433 in words is "two hundred fifteen trillion, one hundred forty billion, thirty million, five hundred fifty-five thousand, four hundred thirty-three".