Base | Representation |
---|---|
bin | 11111010011101010111… |
… | …000000011110000100001 |
3 | 21121200012110012211102021 |
4 | 133103222320003300201 |
5 | 240222104044241001 |
6 | 4324203423221441 |
7 | 311302204032631 |
oct | 37235270036041 |
9 | 7550173184367 |
10 | 2151424212001 |
11 | 75a460975549 |
12 | 2a8b63747881 |
13 | 127b55bbb90c |
14 | 761b54566c1 |
15 | 3ae6bb35ba1 |
hex | 1f4eae03c21 |
2151424212001 has 2 divisors, whose sum is σ = 2151424212002. Its totient is φ = 2151424212000.
The previous prime is 2151424211983. The next prime is 2151424212097. The reversal of 2151424212001 is 1002124241512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2147558357025 + 3865854976 = 1465455^2 + 62176^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151424212001 - 225 = 2151390657569 is a prime.
It is a super-2 number, since 2×21514242120012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2151424212601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075712106000 + 1075712106001.
It is an arithmetic number, because the mean of its divisors is an integer number (1075712106001).
Almost surely, 22151424212001 is an apocalyptic number.
It is an amenable number.
2151424212001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151424212001 is an equidigital number, since it uses as much as digits as its factorization.
2151424212001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 2151424212001 its reverse (1002124241512), we get a palindrome (3153548453513).
The spelling of 2151424212001 in words is "two trillion, one hundred fifty-one billion, four hundred twenty-four million, two hundred twelve thousand, one".
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