Base | Representation |
---|---|
bin | 1100100001101011101… |
… | …1110001010111101011 |
3 | 202120110200012221101011 |
4 | 3020122323301113223 |
5 | 12011212230204011 |
6 | 242510040004351 |
7 | 21355601603551 |
oct | 3103273612753 |
9 | 676420187334 |
10 | 215200241131 |
11 | 832a1a20357 |
12 | 3585a1606b7 |
13 | 173a74a81b5 |
14 | a5b6b4bbd1 |
15 | 58e7b3e621 |
hex | 321aef15eb |
215200241131 has 8 divisors (see below), whose sum is σ = 215711917760. Its totient is φ = 214688743488.
The previous prime is 215200241111. The next prime is 215200241173. The reversal of 215200241131 is 131142002512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-215200241131 is a prime.
It is a super-2 number, since 2×2152002411312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (215200241111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2538985 + ... + 2622373.
It is an arithmetic number, because the mean of its divisors is an integer number (26963989720).
Almost surely, 2215200241131 is an apocalyptic number.
215200241131 is a deficient number, since it is larger than the sum of its proper divisors (511676629).
215200241131 is an equidigital number, since it uses as much as digits as its factorization.
215200241131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89493.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 215200241131 its reverse (131142002512), we get a palindrome (346342243643).
The spelling of 215200241131 in words is "two hundred fifteen billion, two hundred million, two hundred forty-one thousand, one hundred thirty-one".
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