Base | Representation |
---|---|
bin | 1100100001101110000… |
… | …1000000111000100001 |
3 | 202120111100120221111221 |
4 | 3020123201000320201 |
5 | 12011222230112001 |
6 | 242511025135041 |
7 | 21356050564666 |
oct | 3103341007041 |
9 | 676440527457 |
10 | 215210004001 |
11 | 832a7489343 |
12 | 3586148a481 |
13 | 173a9515b45 |
14 | a5b816da6d |
15 | 58e891c1a1 |
hex | 321b840e21 |
215210004001 has 4 divisors (see below), whose sum is σ = 215211469104. Its totient is φ = 215208538900.
The previous prime is 215210003993. The next prime is 215210004041. The reversal of 215210004001 is 100400012512.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 215210004001 - 23 = 215210003993 is a prime.
It is a super-2 number, since 2×2152100040012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (215210004041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 484135 + ... + 815356.
It is an arithmetic number, because the mean of its divisors is an integer number (53802867276).
Almost surely, 2215210004001 is an apocalyptic number.
It is an amenable number.
215210004001 is a deficient number, since it is larger than the sum of its proper divisors (1465103).
215210004001 is a wasteful number, since it uses less digits than its factorization.
215210004001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1465102.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 215210004001 its reverse (100400012512), we get a palindrome (315610016513).
The spelling of 215210004001 in words is "two hundred fifteen billion, two hundred ten million, four thousand, one".
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