Base | Representation |
---|---|
bin | 1100100001110101010… |
… | …1100000010010010011 |
3 | 202120120111001101212011 |
4 | 3020131111200102103 |
5 | 12011303034310311 |
6 | 242514035443351 |
7 | 21356601262054 |
oct | 3103525402223 |
9 | 676514041764 |
10 | 215240541331 |
11 | 83312746502 |
12 | 3586b756557 |
13 | 173b294857a |
14 | a5bc23c72b |
15 | 58eb450321 |
hex | 321d560493 |
215240541331 has 8 divisors (see below), whose sum is σ = 218466891200. Its totient is φ = 212014597608.
The previous prime is 215240541289. The next prime is 215240541353. The reversal of 215240541331 is 133145042512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 215240541331 - 227 = 215106323603 is a prime.
It is a super-2 number, since 2×2152405413312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215240541293 and 215240541302.
It is not an unprimeable number, because it can be changed into a prime (215240341331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1066180 + ... + 1251886.
It is an arithmetic number, because the mean of its divisors is an integer number (27308361400).
Almost surely, 2215240541331 is an apocalyptic number.
215240541331 is a deficient number, since it is larger than the sum of its proper divisors (3226349869).
215240541331 is a wasteful number, since it uses less digits than its factorization.
215240541331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203073.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 215240541331 its reverse (133145042512), we get a palindrome (348385583843).
The spelling of 215240541331 in words is "two hundred fifteen billion, two hundred forty million, five hundred forty-one thousand, three hundred thirty-one".
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