2153113226051 has 4 divisors (see below), whose sum is σ = 2168603249400. Its totient is φ = 2137623202704.

The previous prime is 2153113226021. The next prime is 2153113226059. The reversal of 2153113226051 is 1506223113512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2153113226051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2153113225999 and 2153113226017.

It is not an unprimeable number, because it can be changed into a prime (2153113226059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7745011466 + ... + 7745011743.

It is an arithmetic number, because the mean of its divisors is an integer number (542150812350).

Almost surely, 2^{2153113226051} is an apocalyptic number.

2153113226051 is a deficient number, since it is larger than the sum of its proper divisors (15490023349).

2153113226051 is a wasteful number, since it uses less digits than its factorization.

2153113226051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15490023348.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 2153113226051 its reverse (1506223113512), we get a palindrome (3659336339563).

The spelling of 2153113226051 in words is "two trillion, one hundred fifty-three billion, one hundred thirteen million, two hundred twenty-six thousand, fifty-one".