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2153120131 is a prime number
BaseRepresentation
bin1000000001010110…
…0000000110000011
312120001110211120001
42000111200012003
513402144321011
6553352500431
7104233135111
oct20025400603
95501424501
102153120131
11a05420028
125010aa717
132840c94a6
14165d56ab1
15c905b7c1
hex80560183

2153120131 has 2 divisors, whose sum is σ = 2153120132. Its totient is φ = 2153120130.

The previous prime is 2153120089. The next prime is 2153120141. The reversal of 2153120131 is 1310213512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2153120131 - 27 = 2153120003 is a prime.

It is a super-2 number, since 2×21531201312 = 9271852597034914322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2153120099 and 2153120108.

It is not a weakly prime, because it can be changed into another prime (2153120141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076560065 + 1076560066.

It is an arithmetic number, because the mean of its divisors is an integer number (1076560066).

Almost surely, 22153120131 is an apocalyptic number.

2153120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2153120131 is an equidigital number, since it uses as much as digits as its factorization.

2153120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 2153120131 is about 46401.7255174848. The cubic root of 2153120131 is about 1291.2869257577.

Adding to 2153120131 its reverse (1310213512), we get a palindrome (3463333643).

The spelling of 2153120131 in words is "two billion, one hundred fifty-three million, one hundred twenty thousand, one hundred thirty-one".