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2153150533153 = 10720122902179
BaseRepresentation
bin11111010101010001110…
…001011100111000100001
321121211122202121000211201
4133111101301130320201
5240234123014030103
64325051012241201
7311363035362124
oct37252161347041
97554582530751
102153150533153
11760167386144
122a9365910201
1312806c752819
14762da8303bb
153b01d48851d
hex1f551c5ce21

2153150533153 has 4 divisors (see below), whose sum is σ = 2173273435440. Its totient is φ = 2133027630868.

The previous prime is 2153150533129. The next prime is 2153150533213. The reversal of 2153150533153 is 3513350513512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2153150533153 - 29 = 2153150532641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2153150534153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10061450983 + ... + 10061451196.

It is an arithmetic number, because the mean of its divisors is an integer number (543318358860).

Almost surely, 22153150533153 is an apocalyptic number.

It is an amenable number.

2153150533153 is a deficient number, since it is larger than the sum of its proper divisors (20122902287).

2153150533153 is a wasteful number, since it uses less digits than its factorization.

2153150533153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20122902286.

The product of its (nonzero) digits is 101250, while the sum is 37.

The spelling of 2153150533153 in words is "two trillion, one hundred fifty-three billion, one hundred fifty million, five hundred thirty-three thousand, one hundred fifty-three".

Divisors: 1 107 20122902179 2153150533153