Base | Representation |
---|---|
bin | 1100100010001101101… |
… | …0101011001110000011 |
3 | 202120211121000111100020 |
4 | 3020203122223032003 |
5 | 12012010143411011 |
6 | 242532122224523 |
7 | 21362250363006 |
oct | 3104332531603 |
9 | 676747014306 |
10 | 215342560131 |
11 | 83365296766 |
12 | 35899955143 |
13 | 173cab17c1a |
14 | a5cb9d753d |
15 | 59053a3006 |
hex | 32236ab383 |
215342560131 has 8 divisors (see below), whose sum is σ = 287275418640. Its totient is φ = 143485704192.
The previous prime is 215342560129. The next prime is 215342560151. The reversal of 215342560131 is 131065243512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 215342560131 - 21 = 215342560129 is a prime.
It is a super-2 number, since 2×2153425601312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 215342560092 and 215342560101.
It is not an unprimeable number, because it can be changed into a prime (215342560151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18994030 + ... + 19005363.
It is an arithmetic number, because the mean of its divisors is an integer number (35909427330).
Almost surely, 2215342560131 is an apocalyptic number.
215342560131 is a deficient number, since it is larger than the sum of its proper divisors (71932858509).
215342560131 is a wasteful number, since it uses less digits than its factorization.
215342560131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38001285.
The product of its (nonzero) digits is 21600, while the sum is 33.
The spelling of 215342560131 in words is "two hundred fifteen billion, three hundred forty-two million, five hundred sixty thousand, one hundred thirty-one".
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