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21534443444153 is a prime number
BaseRepresentation
bin1001110010101111000001…
…10110100001011110111001
32211020200011101111220020002
410321113200312201132321
510310310020010203103
6113444441534242345
74351545404055653
oct471274066413671
984220141456202
1021534443444153
116952784a16852
1224b96296563b5
13c028c6526813
145463b61196d3
15275260ec5488
hex1395e0da17b9

21534443444153 has 2 divisors, whose sum is σ = 21534443444154. Its totient is φ = 21534443444152.

The previous prime is 21534443444141. The next prime is 21534443444179. The reversal of 21534443444153 is 35144434443512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11442436032889 + 10092007411264 = 3382667^2 + 3176792^2 .

It is a cyclic number.

It is not a de Polignac number, because 21534443444153 - 244 = 3942257399737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21534443444098 and 21534443444107.

It is not a weakly prime, because it can be changed into another prime (21534443444753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10767221722076 + 10767221722077.

It is an arithmetic number, because the mean of its divisors is an integer number (10767221722077).

Almost surely, 221534443444153 is an apocalyptic number.

It is an amenable number.

21534443444153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21534443444153 is an equidigital number, since it uses as much as digits as its factorization.

21534443444153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5529600, while the sum is 47.

Adding to 21534443444153 its reverse (35144434443512), we get a palindrome (56678877887665).

The spelling of 21534443444153 in words is "twenty-one trillion, five hundred thirty-four billion, four hundred forty-three million, four hundred forty-four thousand, one hundred fifty-three".