Base | Representation |
---|---|
bin | 1001110010110001000001… |
… | …00110100011110110001011 |
3 | 2211020202220221002000212210 |
4 | 10321120200212203312023 |
5 | 10310314212312020410 |
6 | 113445140022440203 |
7 | 4351614042130353 |
oct | 471304046436613 |
9 | 84222827060783 |
10 | 21535513001355 |
11 | 6953183728a21 |
12 | 24b9887893063 |
13 | c02a36ca8ac2 |
14 | 5464781b1b63 |
15 | 2752c4d46220 |
hex | 1396209a3d8b |
21535513001355 has 16 divisors (see below), whose sum is σ = 34843976094240. Its totient is φ = 11356555170048.
The previous prime is 21535513001333. The next prime is 21535513001381. The reversal of 21535513001355 is 55310031553512.
It is not a de Polignac number, because 21535513001355 - 217 = 21535512870283 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8065733872 + ... + 8065736541.
It is an arithmetic number, because the mean of its divisors is an integer number (2177748505890).
Almost surely, 221535513001355 is an apocalyptic number.
21535513001355 is a deficient number, since it is larger than the sum of its proper divisors (13308463092885).
21535513001355 is a wasteful number, since it uses less digits than its factorization.
21535513001355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16131470510.
The product of its (nonzero) digits is 168750, while the sum is 39.
Adding to 21535513001355 its reverse (55310031553512), we get a palindrome (76845544554867).
The spelling of 21535513001355 in words is "twenty-one trillion, five hundred thirty-five billion, five hundred thirteen million, one thousand, three hundred fifty-five".
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