Base | Representation |
---|---|
bin | 11111010101101111100… |
… | …111110110100000000011 |
3 | 21121212221122221022020202 |
4 | 133111233213312200003 |
5 | 240241134220124443 |
6 | 4325212422155415 |
7 | 311411326200263 |
oct | 37255747664003 |
9 | 7555848838222 |
10 | 2153651333123 |
11 | 7603a4039614 |
12 | 2a9485582b6b |
13 | 12811c427a74 |
14 | 763471537a3 |
15 | 3b04c40d7b8 |
hex | 1f56f9f6803 |
2153651333123 has 4 divisors (see below), whose sum is σ = 2155456574328. Its totient is φ = 2151846091920.
The previous prime is 2153651333101. The next prime is 2153651333131. The reversal of 2153651333123 is 3213331563512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2153651333123 - 220 = 2153650284547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2153651333143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 902618813 + ... + 902621198.
It is an arithmetic number, because the mean of its divisors is an integer number (538864143582).
Almost surely, 22153651333123 is an apocalyptic number.
2153651333123 is a deficient number, since it is larger than the sum of its proper divisors (1805241205).
2153651333123 is a wasteful number, since it uses less digits than its factorization.
2153651333123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1805241204.
The product of its digits is 145800, while the sum is 38.
Adding to 2153651333123 its reverse (3213331563512), we get a palindrome (5366982896635).
The spelling of 2153651333123 in words is "two trillion, one hundred fifty-three billion, six hundred fifty-one million, three hundred thirty-three thousand, one hundred twenty-three".
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