Base | Representation |
---|---|
bin | 11111010110000111000… |
… | …010010010101101001001 |
3 | 21121220222001001222110222 |
4 | 133112013002102231021 |
5 | 240242440244442421 |
6 | 4325315413315425 |
7 | 311424136044011 |
oct | 37260702225511 |
9 | 7556861058428 |
10 | 2154044140361 |
11 | 7605858414a3 |
12 | 2a9575035b75 |
13 | 12818291b499 |
14 | 763833a4c41 |
15 | 3b071b50cab |
hex | 1f587092b49 |
2154044140361 has 2 divisors, whose sum is σ = 2154044140362. Its totient is φ = 2154044140360.
The previous prime is 2154044140349. The next prime is 2154044140447. The reversal of 2154044140361 is 1630414404512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1313052433225 + 840991707136 = 1145885^2 + 917056^2 .
It is a cyclic number.
It is not a de Polignac number, because 2154044140361 - 234 = 2136864271177 is a prime.
It is not a weakly prime, because it can be changed into another prime (2154044140301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077022070180 + 1077022070181.
It is an arithmetic number, because the mean of its divisors is an integer number (1077022070181).
Almost surely, 22154044140361 is an apocalyptic number.
It is an amenable number.
2154044140361 is a deficient number, since it is larger than the sum of its proper divisors (1).
2154044140361 is an equidigital number, since it uses as much as digits as its factorization.
2154044140361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 2154044140361 its reverse (1630414404512), we get a palindrome (3784458544873).
The spelling of 2154044140361 in words is "two trillion, one hundred fifty-four billion, forty-four million, one hundred forty thousand, three hundred sixty-one".
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