Base | Representation |
---|---|
bin | 110000111110110011101001… |
… | …111010100100111011111001 |
3 | 1001020202011121202201202222121 |
4 | 300332303221322210323321 |
5 | 211213434334330121040 |
6 | 2042055350150321241 |
7 | 63242514342516436 |
oct | 6076635172447371 |
9 | 1036664552652877 |
10 | 215422304145145 |
11 | 627050a4707629 |
12 | 201b2351959221 |
13 | 932830b98b3c6 |
14 | 3b2a6d09b0b8d |
15 | 19d89662a7c4a |
hex | c3ece9ea4ef9 |
215422304145145 has 16 divisors (see below), whose sum is σ = 259140787200000. Its totient is φ = 171915611744448.
The previous prime is 215422304145067. The next prime is 215422304145157. The reversal of 215422304145145 is 541541403224512.
It is a cyclic number.
It is not a de Polignac number, because 215422304145145 - 235 = 215387944406777 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24287970 + ... + 31949179.
It is an arithmetic number, because the mean of its divisors is an integer number (16196299200000).
Almost surely, 2215422304145145 is an apocalyptic number.
It is an amenable number.
215422304145145 is a deficient number, since it is larger than the sum of its proper divisors (43718483054855).
215422304145145 is a wasteful number, since it uses less digits than its factorization.
215422304145145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56239032.
The product of its (nonzero) digits is 768000, while the sum is 43.
Adding to 215422304145145 its reverse (541541403224512), we get a palindrome (756963707369657).
The spelling of 215422304145145 in words is "two hundred fifteen trillion, four hundred twenty-two billion, three hundred four million, one hundred forty-five thousand, one hundred forty-five".
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