Base | Representation |
---|---|
bin | 1100100010100011101… |
… | …1110001001001000001 |
3 | 202121002001012002021121 |
4 | 3020220323301021001 |
5 | 12012202342334332 |
6 | 242545230152241 |
7 | 21364453213261 |
oct | 3105073611101 |
9 | 677061162247 |
10 | 215435121217 |
11 | 83402567228 |
12 | 35904952681 |
13 | 174140557b4 |
14 | a5da00d7a1 |
15 | 590d588797 |
hex | 3228ef1241 |
215435121217 has 2 divisors, whose sum is σ = 215435121218. Its totient is φ = 215435121216.
The previous prime is 215435121211. The next prime is 215435121283. The reversal of 215435121217 is 712121534512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 136988074161 + 78447047056 = 370119^2 + 280084^2 .
It is a cyclic number.
It is not a de Polignac number, because 215435121217 - 211 = 215435119169 is a prime.
It is a super-2 number, since 2×2154351212172 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (215435121211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107717560608 + 107717560609.
It is an arithmetic number, because the mean of its divisors is an integer number (107717560609).
Almost surely, 2215435121217 is an apocalyptic number.
It is an amenable number.
215435121217 is a deficient number, since it is larger than the sum of its proper divisors (1).
215435121217 is an equidigital number, since it uses as much as digits as its factorization.
215435121217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 16800, while the sum is 34.
Adding to 215435121217 its reverse (712121534512), we get a palindrome (927556655729).
The spelling of 215435121217 in words is "two hundred fifteen billion, four hundred thirty-five million, one hundred twenty-one thousand, two hundred seventeen".
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